Question: what is the square root of negative one (often
written as (-1)½ )?
For that matter, what is the square root of negative anything?
You may have been told that square roots of negative numbers are
undefined; and equations involving them are impossible to solve. This
is not strictly true. For example, lets say we define the letter i
as follows:
Let i
= (-1)½
Now what is
the square root of negative anything? For example, what is the square
root of negative 49? Easy:
(-49)½
= (49
× -1)½
= 49½
× (-1)½
= 7 ×
i
= 7i
Of course, we haven't actually solved the square root - we've just
buried the problem inside i.
Numbers which are directly proportional to i,
like i, 7i and bi
(where b
is a constant) are called imaginary
numbers, and are technically meaningless. (All other
numbers are called real numbers.)
So why bother with them at all? Because there are many instances where,
in solving a difficult equation, terms involving square roots of
negative numbers pop up. Introducing imaginary numbers allows us to
proceed to the next step, and they often disappear from equations
before the final solution anyway. For example, i2
= -1, thus higher order imaginary terms can 'decay' into real numbers.
Note that, likewise, all powers of i
decay to either real or imaginary numbers of power 1. For example,
consider i5:
i5
= i2 i3
= -1
× i3
= -i2 i
= -(-1)i
= i
Complex numbers
Now that you know what an imaginary number is, complex numbers are
simple. A complex number is simply a real number plus an imaginary
number. So there are in fact three types of numbers: real, imaginary
and complex.
Complex numbers are of the form:
Z = a + bi
where a is
the real component of complex number Z (often written as
Re{Z}) and b = Im{Z} is
the imaginary component.
Addition, multiplication, etc. of complex numbers is also simple. Just
treat i
exactly the same as any other algebraic symbol (x, y, a, b, etc.),
and proceed as normal.